10=263t+-16t^2

Solution for 10=263t+-16t^2 equation:

10=263t+-16t^2

We move all terms to the left:

10-(263t+-16t^2)=0

We use the square of the difference formula

-(263t-16t^2)+10=0

We get rid of parentheses

16t^2-263t+10=0

a = 16; b = -263; c = +10;
Δ = b2-4ac
Δ = -2632-4·16·10
Δ = 68529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-263)-\sqrt{68529}}{2*16}=\frac{263-\sqrt{68529}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-263)+\sqrt{68529}}{2*16}=\frac{263+\sqrt{68529}}{32}
$